In a previous post I showedÂ How To Turn A Table Into A Column Using Formulas, and in this post we’re going to explore how to do the inverse action and turn a column into a table.

You could do this in a number of different ways but these are the two that make the most sense given a column of data comprised of small blocks of related data like in the example. In this example every three rows of the column relate to one person.

- We could convert this to a table where each
**column**in the table contains the data relating toÂ one person. - We could convert this to a table where each
**row**in the table contains the data relating to one person.

## Option 1

To create a table where **each column contains related data** we can use this formula.

`=INDEX($B$3:$B$14,ROWS($D$3:$G$5)*(COLUMN()-COLUMN($D$3:$G$5))+(ROW()-ROW($D$3:$G$5)+1),1)`

**$B$3:$B$14** is the original column of data and **$D$3:$G$5** is a 4 column and 3 row range because our original data has 4Â blocks of related data and 3Â items in each block.

## Option 2

To create a table where **each row contains related data** we can use this formula.

`=INDEX($B$3:$B$14,COLUMNS($E$11:$G$14)*(ROW()-ROW($E$11:$G$14))+(COLUMN()-COLUMN($E$11:$G$14)+1),1)`

**$B$3:$B$14** is the original column of data and **$E$11:$G$14** is a 3Â column 4Â row range because our original data has 4Â blocks of related data and 3Â items in each block.

## Formula Breakdown

The **INDEX** function returns a value from a range based on a row number and column number. So, `=INDEX($B$3:$B$14,`

refers to **4**,**1**)**row 4** and **column 1** of the range **$B$3:$B$14**, in our example this contains the value **Yoda**.

Since our range only has one column, the column index in our formula will always be 1 and our formula will look like this `=INDEX($B$3:$B$14,`

. We need to be clever about how we get the row number.**number representing the right row**,1)

Above are the **row index numbers we would like ** (for option 2) when the formula is copied across the table. Of course, for this formula we will need to know in advance there are **4 blocks** of data containing **3 fields** each so we can set up the range of our output table as a **4 row** and **3 column** table. In our option 2 example this table isÂ **$E$11:$G$14**.

If we want this series of numbers we need a formula like this **number of columns in the range** * **current row of the range** + **current column of the range** + **1**. `COLUMNS($E$11:$G$14)`

will give us the number of columns in the range $E$11:$G$14. `ROW()-ROW($E$11:$G$14)`

will give us the current row number (starting at 1) of the range while `COLUMN()-COLUMN($E$11:$G$14)`

gives us the current column number (starting at 1) of the range.

Putting it all together we get our formula for the row index:

`COLUMNS($E$11:$G$14)*(ROW()-ROW($E$11:$G$14))+(COLUMN()-COLUMN($E$11:$G$14)+1)`